find the surface area and the diagonal of a cube,whose edge is 18cm
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Answer is : 1944cm
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diagonal of a cube?
Answered by
1
total surface area of cube = 6*l*l
curved surface area of cube = 4*l*l
hence,
total surface area of given cube =
6 * 18 * 18 = 1944 sq.cm
curved surface area of given cube =
4 * 18 * 18 = 1296 sq.cm
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Explanation: diagonal of cube
General formula for the diagonal of a cube if each side of the cube = l
Use Pythagorean Theorem to get the diagonal across the base:
l2 + l2 = h2
And again use Pythagorean Theorem to get cube’s diagonal, then solve for d:
h2 + l2 = d2
l2 + l2 + l2 = d2
3 * l2 = d2
d = √ (3 * l2) = l √3
So, if l = 18 then the answer is 18√3
curved surface area of cube = 4*l*l
hence,
total surface area of given cube =
6 * 18 * 18 = 1944 sq.cm
curved surface area of given cube =
4 * 18 * 18 = 1296 sq.cm
PLEASE MARK AS BRAINLIEST
Explanation: diagonal of cube
General formula for the diagonal of a cube if each side of the cube = l
Use Pythagorean Theorem to get the diagonal across the base:
l2 + l2 = h2
And again use Pythagorean Theorem to get cube’s diagonal, then solve for d:
h2 + l2 = d2
l2 + l2 + l2 = d2
3 * l2 = d2
d = √ (3 * l2) = l √3
So, if l = 18 then the answer is 18√3
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