Question

Find the surface area and the volume of a rectangular solid measuring 5m by 4m by 3m Also find the lenght of a diagonal

Answer 1

total surface area of cuboid
= 2(lb+bl+lh)
=2(5×4+4×3+3×3)
=2(20+12+9)
=2×41
=82 sq.m.

volume of cuboid
=lbh
=5×4×3
=60cu.m.

length of diagonal of cuboid
$= \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }$
$= \sqrt{25 + 16 + 9} \\ = \sqrt{50 } \\ =5 \sqrt{2}$

Answer 2

Area = 94 m², V=60m³ and length of a diagonal = 5√2 m.

Step-by-step explanation:

It is given that measure of a solid rectangle is 5m × 4m × 3m .

Length : l = 5m

Breadth : b = 4m

Height : h = 3m

Surface area of a cuboid:

$A=2(lb+bh+hl)$

Substitute the given  values.

$A=2((5)(4)+(4)(3)+(3)(5))$

$A=2(47)$

$A=94$

Therefore, the surface area is 94 m².

Volume of a cuboid:

$V=l\times b\times h$

$V=5\times 4\times 3$

$V=60$

Therefore, the volume of a rectangular solid is 60m³.

Length of a diagonal of a cuboid is

$Diagonal=\sqrt{l^2+b^2+h^2}$

$Diagonal=\sqrt{5^2+4^2+3^2}$

$Diagonal=\sqrt{50}$

$Diagonal=5\sqrt{2}$

Therefore, the length of a diagonal is 5√2 m.

#Learn more

The L,B,H of a cuboid are in the ratio 7:6:5 .if the volume of a cuboid is 5670 cm^2. find the surface area of cuboid.

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