Question

Find the surface area generated by revolving the loop of the curve 9a(y^2)=x(3a-x)^2 about x-axis

Answer 1

Answer:

Watch ⌚ for Find the surface area generated by revolving the loop of the curve 9a(y^2)=x(3a-x)^2 about x-axisFind the surface area generated by revolving the loop of the curve 9a(y^2)=x(3a-x)^2 about x-axis

Step-by-step explanation:

Find the surface area generated by revolving the loop of the curve 9a(y^2)=x(3a-x)^2 about x-axisFind the surface area generated by revolving the loop of the curve 9a(y^2)=x(3a-x)^2 about x-axis