Find the surface area of a chalk box whose length, breadth and height are 16 cm, 8 cm and 6 cm, respectively
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Step-by-step explanation:
L is 16 cm. B is 8 cm. 6 cm is H
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Given :-
- Length = 16
- Breadth = 8 cm
- Height = 6 m
To Find :-
- Surface area of chalk box = ?
Solution :-
- It is given that chalk box whose length, breadth and height are 16 cm, 8 cm and 6 cm, respectively. chalk box is in the cuboidal shape. So, here we will use the formula of surface area of cuboid :]
Let Length be 'l' , Breadth be 'b' and height be 'h' .
→ Surface Area of cuboid = 2(lb + bh + hl)
→ Surface Area of cuboid = 2(16 × 8 + 8 × 6 + 6 × 16)
→ Surface Area of cuboid = 2(128 + 48 + 96)
→ Surface Area of cuboid = 2(272)
→ Surface Area of cuboid = 544 cm²
Therefore,the surface area of a chalk box is 544 cm².
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