Question

Find the surface area of a sphere whose volume is 4851 cm cube

Answer 1

We know that,
Volume of sphere=4/3Πr³

According to the question,
4/3Πr³=4851cm³

(4/3)(22/7)r³=4851cm³

(88/21)re=4851cm³

r³=4851cm³×(21/88)

r³=1157.625cm³

r=³√115.625cm³

r=10.5cm

Total Surface Area of sphere =4Πr²
=4(22/7)(10.5)²
=1386cm²

Therefore surface area of the sphere is 1386cm².

Hope it helps you.

Answer 2

Answer:

we know that,

volume of sphere =4/3πr³

4/3πr³=4851cm³

4/3×22/7×r³=4851cm³

88/21×r³=4851cm³

r³=4851×21/88

r³=1157.625cm³

r³=√115.625cm³

r=10.5cm

total surface area of a sphere=4πr²

=4×22/7×10.5²

=1386cm²

therefore surface area of the sphere is

=1386cm²