Find the surface area of a square pyramid with side length of 2 inches in a slant height of 5 inches
Answers
Answered by
0
Answer:
Given
a
=
8
in
,
h
=
5
in
Area of the square base
A
b
=
a
2
=
8
⋅
8
=
64
sq in
Slant height of the triangle
s
=
√
(
a
2
)
2
+
h
2
s
=
√
(
8
2
)
2
+
5
2
=
6.403
A
r
e
a
o
f
s
l
a
n
t
△
'
A
s
=
(
1
2
)
a
⋅
s
=
(
1
2
)
⋅
8
⋅
6.403
=
25.612
Surface Area of the square pyramid
T
S
A
=
A
b
+
4
⋅
A
s
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