Question

find the surface area of cube whose volume is 512 M cube

Answer 1

$volume \: of \: cube = 512 {m}^{3} \\ {a}^{3} = 512 \\ a = \sqrt[3]{512} \\ a = 8 \\ surface \: area = 6 {a}^{2} \\ \: \: \: \: \: \: \: \: \: = 6 \times 8 \times 8 \\ = 6 \times 64 \\ = 384 {m}^{2}$

Answer 2

surface area of cube = 6a^²

volume of cube = a^³

512=a^³

8= a

now surface area of cube= 6×(8)^²

surface area of cube= 384m^²

hope it helps