find the surface area of cube whose volume is 729cube.
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Answered by
1
side of cube=√729=9
surface area of cube=6×(9)2
=6×81
=486
surface area of cube=6×(9)2
=6×81
=486
Answered by
1
volume of cube = 729 unit cube
.: (side)³= 729
side. = ³√729 =9 units
surface area of cube = 6(side)² =6(9)² =6(81)
= 486 unit square.
.: (side)³= 729
side. = ³√729 =9 units
surface area of cube = 6(side)² =6(9)² =6(81)
= 486 unit square.
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