find the surface area of foot ball with diameter by 28 cm
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1
Answer:
∴ radius =2d=228=14 cm.
Then, surface area of a sphere of radius (r) =4πr2.
=2464 cm2.
Therefore, the required surface area of the sphere is 2464 cm2.
Answered by
1
FOOTBALL IS IN THE SHAPE SPHERE.
SURFACE AREA OF SPHERE = 4πr²
= 4 x 22/7 x ( 28/2 )²
= 4 x 22/7 x 14²
= 4 x 22/7 x 196
= 88/7 x 196
= 2464 cm²
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