find the surface area of the cuboid whose dimensions are l is equal to 5 cm b is equal to 4 cm h
is equal to 3 cm
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Surface area = 2(lb+bh+lh)
SA = 2(5×4 + 4×3 + 5×3) = 2(20+12+15) = 94cm^2
SA = 2(5×4 + 4×3 + 5×3) = 2(20+12+15) = 94cm^2
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Surface area of cuboid= 2lb+2bh+2hl
=2*5*4+2*4*3+2*3*5
=40+24+30
=94cm²
=2*5*4+2*4*3+2*3*5
=40+24+30
=94cm²
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