Question

find the swsllest which when increased by 17 is exactly divisible by both 520 and 468.

Answer 1

when increased by 17 the smallest number which is exactly divisible by both 520 and 468 is 26
$520 \div 26 = 20$
$468 \div 26 = 18$
i this is the best answer

Answer 2

FIRST WE NEED TO FIND THE LCM OF 520 AND 468
520 = 2×2×2×5×13
468 = 2×2×3×3×13

SO
LCM = 2×2×2×3×3×5×13
LCM = 4680

SO 4680 IS THE SMALLEST NUMBER WHICH IS EXACTLY DIVISIBLE BY 520 AND 468

4680 - 17
= 4663

SO 4663 IS THE SMALLEST NUMBER WHICH INCREASED BY 17 THEN IT EXACTLY DIVISIBLE BY 520 AND 468