Question

find the symmetrical form of the line x-y+2z=5, 3x+y+z=6​

Answer 1

Answer:x/a + y/b = 1

Step-by-step explanation:Equation of straight line passing through point P (x1, y1, z1) and whose direction cosines are l, m, n is

(x–x1)/l = (y – y1)/m = (z – z1) / n.

Equation of straight line passing through two points P (x1, y1, z1) and Q (x2, y2, z2) is  

x–x1 / x2– x1 = y–y1 / y2 – y1 = z – y1 / z2 – z1

Section formula: If P(x, y) divides the line joining A(x1, y1) and B(x2, y2) in the ratio of m:n then,  

x = (mx2 + nx1)/ (m+n) and y = (my2 + ny1)/ (m+n)