Question

find the T ratio of 150°

Answer 1

$\mathfrak{\blue{\huge \: hello\:mate\:!!!\:...}}$

. sin 150° = sin (2 × 90° - 30°) = sin 30° = 1/2; 

cos 150° = cos (2 × 90° - 30°) = cos 30° = - √32√32; 

tan 150° tan (2 × 90° - 30°) = - tan 30° = - 1√31√3;

csc 150° = csc (2 × 90° - 30°) = csc 30° = 2; 

sec 150° = sec (2 × 90° - 30°) = sec 30° = - 2√32√3; 

cot 150° = cot (2 × 90° - 30°) = - cot 300 = - √3.

$<marquee>$ ❣️⭐I hope you mark as brainlist⭐❣️✨✨