Find the tenth term of the sequence √2,√8,√18,.........
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√2,√8,√18,√32,
a10=√2+18
a10=√2+18
adytt123:
noooooonooo it will be 9+root2
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a1=√2,
a2=√8=√4*√2=2√2
So, d=a2-a1= √2
So, a10=a+9d=√2+9√2=10√2//
a2=√8=√4*√2=2√2
So, d=a2-a1= √2
So, a10=a+9d=√2+9√2=10√2//
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