Find the term 5, 22, ?, 140, 265
Answers
Answer:
63
Step-by-step explanation:
Let x be the Number.
5 22 x 140 265
17 x-22 140-x 125
x-39 162-2x x-15
162-3x+39 3x-15-162
Now, for sequence to converge,
162 - 3x + 39 = 3x - 15 - 162
Therefore, 201 - 3x = 3x -177
Therefore, 6x = 378
Therefore, x = 63
So, missing number is 63. Series will converge at 4th level with it.
Answer:
The missing number is 63.
Step-by-step explanation:
Given sequence,
5, 22, ?, 140, 265,
By examining the sequence it is hard to find the missing number that follows the sequence,
Let n be the missing number,
The sequence would be,
5, 22, p, 140, 265
Since, In a logical sequence the final difference in the consecutive terms is always equal,
First difference = 22 - 5, p - 22, 140, - p, 265 - 140
Second difference = (p-22)-(22-5), (140-p)-(p-22), (265-140)-(140-p)
Third difference = [(140-p)-(p-22)]-[(p-22)-(22-5)], [(265-140)-(140-p)]-[(140-p)-(p-22)]
By the above statement,
[(140-p)-(p-22)]-[(p-22)-(22-5)] = [(265-140)-(140-p)]-[(140-p)-(p-22)]
140 - p - p + 22 - p + 22 + 22 - 5 = 265 - 140 - 140 + p - 140 + p + p - 22
201 - 3p = -177 + 3p
⇒ 6p = 378 ⇒ p = 63
Hence, missing number is 63.