Math, asked by Nupurguptak3052, 11 months ago

Find the term independent of x in the expansion of (x+1/x)^10

Answers

Answered by Sharad001
77

Question:-

 \sf \red{ Find  \: the \:  term} \green{  \: independent  \: of  \: x  }\\  \sf  \purple{in  \: the \:  expansion \: of }\:  (x+ \frac{1}{x} )^{10}</p><p> \:

Answer:-

 \red{ \sf Term \:  independent  \: of  \: x \:  is \: } \sf 252  \:  \: or \:  ^{10}C_{5} \: \:  \:

To Find :-

→ Term independent of x .

Explanation:-

We have expansion -

 \leadsto \sf  { \bigg(x +  \frac{1}{x} \bigg) }^{10}  \\  \\ \sf  \green{term \: independent \: of \: x }\: means \: the \: term \:   \\ \sf  \orange{which \: is \: not \: depend \: on \: }x \: ( {x}^{0})  \\  \bf \: hence \\  \\  \because  \sf \red{ for \: coefficient \: of} \: x \:  \: \blue{  \{ ^{n}C_{r} \:  {a}^{n - r}  {x}^{r}  \} }\:  \\  \\  \to \sf ^{10}C_{r} \: \:  {x}^{(10 - r)}  \:  { \bigg( \frac{1}{x}  \bigg)}^{r}  \\  \\  \to \sf \: ^{10}C_{r} \: {x}^{(10 - r)}  {x}^{( - r)}  \\  \\  \to \sf \: ^{11}C_{r} \: \:  {x}^{(10 - r - r)}  \\  \\ \bf \red{ for \: term \:} \green{ independent \: of \: x} \\  \\  \to \sf 10 - r - r = 0 \\  \\  \to \sf \: 2r = 10 \\  \\  \to \boxed{ \sf r = 5} \\  \\ \sf  hence \\  \\  \leadsto \sf ^{10}C_{5} \: {x}^{(10 - 5 - 5)}  \\  \\  \to \sf ^{10}C_{5} \: {x}^{1}  \\  \sf or \:  \\  \to \sf  \frac{10 \times 9 \times 8 \times 7 \times 6 }{5 \times 4 \times 3 \times 2 \times 1}  \\  \\  \leadsto \sf \: 252 \\  \\ \sf Term \:  independent  \: of  \: x \:  is \:  252  \:  \: or \:  ^{10}C_{5} \: \:

Hope it helps you .

Answered by deepanshu67892
0

Answer:

The term independent of x in the expansion  (x+1/x)^{10} is  ^{10}C_{5} = 252 .

Step-by-step explanation:

The binomial expansion of the  (x+1/x)^{10} is given by binomial theorem. The terms are represented as

 ^{10}C_{n}x^{n}(1/x)^{10-n} .

The power of x in this term should be zero in order to find the term independent of x. The power of x in this term  ^{10}C_{n}x^{n}(1/x)^{10-n} is found by writing

x^{n}(1/x)^{10-n}

 x^{n-10+n}

For term independent of x its power must be zero. So, n-10+n must be 0.

 n-10+n = 0

 2n-10=0

 n=5

Putting 5 in

 ^{10}C_{n}x^{n}(1/x)^{10-n}

there is  ^{10}C_{5}. On calculating, the value of  ^{10}C_{5} = 252.

So, the correct answer is 252.

Similar questions