Math, asked by 1mrsmunni, 2 months ago

Find the term of (x +1/X)^6
that does not contain x​

Answers

Answered by AnnJohnOT7
2

Step-by-step explanation:

Answer:

Tr+1=6Cr.(x)^(6-r).(-1/x)^r

or. =6Cr.(-1)^r.(x)^(6-r-r).

or. =6Cr.(-1)^r. (x)^(6–2r)……………(1)

For constant term power of x should zero.

6–2r=0. =>. r=3

On putting r=3 in eqn.(1)

T(3+1) =6C3.(-1)^3.(x)^(6–6)

T4. = - 6.5.4.(3!)/(3!).(3.2.1) .(x)^0

T4= -20.(1)

T4 = -20. Answer

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