Question

Find the
the equation of the line passing though
the point (3, 4) and (-5, I)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$y - y 1 \div x - x1 = y2 - y1 \div x2 - x1$

$x1 = 3 \\ y1 = 4 \\ x2 = - 5 \\ y2 = 1$

y-4÷x-3=1-4÷(-5-3)

y-4÷x-3=(-3÷(-8)

y-4÷x-3=3÷8

8(y-4)=3(x-3)

8y-32=3x-9

-32+9=3x-8y

-23=3x-8y

3x-8y+23=0

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