Find the the solution of x2+5x+5=0 if x is a rational number
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X^2+5X+5=0
a=1 ,b=5, c=5
Using Quadratic equation formula
X= -(b) +_√(b^2-4ac)
____________
2a
X= -5+_√(25 -20).
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2
So X =
-5+√5
_________.
2
&
-5 -√5
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2
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