Question

find the the sum of first 10 terms of AP:log 2, log 4 ,log 8,log 16........​

Answer 1

Answer:

Since

4=2²

So, log 4 = 2 log 2

8=2³

So, log 8 = 3 log 2

and so on,

The first term a = log 2 and the common difference of the AP so formed is log 2.

So, the sum of the first 10 terms will be

Sum = 10/2{2(log2)+(10-1)log2} = 5{2log2+9log2} = 55 log 2

Hope this helps you !

Answer 2

Answer:

110

Step-by-step explanation:

a=2 ,d=2 ,n=10

Sn = n÷2(2a+(n-1)×d)

=10÷2(2×2(10-1)×2)

=5(4+9×2)

=5×22

=110