Question

Find the third side of a triangle whose perimeter is (7x^22+7x-7)and the two sides are (5x+56)and (6x^2+3x-1)

Answer 1

Answer:

x^2 - x -12

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Step-by-step explanation:

assuming that you typed 7x^2 + 7x -7

perimeter of a triangle = x1+x2+x3

7x^2 +7x-7 = 5x+6 +6x^2 +3x -1 + x3

x^2 - x -12 =x3