Find the third vertex of triangle ABC if two of its vertices a a(- 5 ,-6 )(1, 9) and its centroid is G (6 - 3)
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The formula of centroid is A + B + C / 3
G(x)= A(x)+B(x)+C(x)/E
6= -5+1 + C(x)/3
6*3 = -4 + C(x)
18+4 = C(x)
C(x) = 22
G(y) = A(y) + B(y) + C(y) /3
-3 = -6+9 + C(y)/3
-3*3 = 3 + C(y)
-9-3 = C(y)
C(y) = -12
therefore C(x,y) = (22,-12)
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G(x)= A(x)+B(x)+C(x)/E
6= -5+1 + C(x)/3
6*3 = -4 + C(x)
18+4 = C(x)
C(x) = 22
G(y) = A(y) + B(y) + C(y) /3
-3 = -6+9 + C(y)/3
-3*3 = 3 + C(y)
-9-3 = C(y)
C(y) = -12
therefore C(x,y) = (22,-12)
mark me as brainiest
Bhavyadharu:
mark me as brainliest
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