Question

Find the three altitudes of the triangle shown here
if the area of the triangle is 42 cm2.​

Answer 1

Step-by-step explanation:

Sides of the triangle are a=42,b=34,c=20

According to Hero's formula,

Area of the triangle, A=

s(s−a)(s−b)(s−c)

Where s=

2

a+b+c

=

2

42+34+20

=48

Now,

A=

48(48−42)(48−34)(48−20)

A=

48(6)(14)(28)

A=

(6×8)(6)(14)(14×2)

A=14×6×4

A=336cm

2

Let the height corresponding to longest side (42cm) is h

Area =

2

1

×base×height

2

1

×42×h=336

h=

42

336×2

=16 cm