Question

Find the three consecutive even numbers whose sum is 66

Answer 1

let the three consecutive even numbers be (x +2) , (x+4), and (x+6)

According to the question,
(x +2) + (x+4) + (x+6) = 66

=> x + 2 + x + 4 + x + 6 = 66

=> 3x + 12 = 66

=> 3x = 66 - 12

=> 3x = 54

=> x = $\frac{54}{3}$

=> x = 18

therefore,

(x + 2) = (18 + 2) = 20
(x + 4) = (18 + 4) = 22
(x + 6) = (18 + 6) = 24

So, the three consecutive even numbers are : 20, 22 and 24