Find the three consecutive natural number so that their sum will be 60.
Answers
Answered by
1
let the three consecutive natural numbers be(x+1), (x+2), (x+3) then,
(x+1) + (x+2) +(x+3) = 60
x+1+x+2+x+3 =60
3x + 6 =60
3x =60-6
3x =54
x = 54/3
x =18
hence, the three consecutive natural numbers are (18+1)=19, (18+2)=20, (18+3)=21
check: 19 +20 +21=60
(x+1) + (x+2) +(x+3) = 60
x+1+x+2+x+3 =60
3x + 6 =60
3x =60-6
3x =54
x = 54/3
x =18
hence, the three consecutive natural numbers are (18+1)=19, (18+2)=20, (18+3)=21
check: 19 +20 +21=60
Answered by
3
Hi friend,
Let the three consecutive natural numbers be(x+1), (x+2), (x+3).
(x+1) + (x+2) +(x+3) = 60
x+1+x+2+x+3 =60
3x + 6 =60
3x =60-6
3x =54
x = 54/3
x =18
hence, the three consecutive natural numbers are
(18+1)=19,
(18+2)=20,
(18+3)=21
The total value 19+20+21=60.
Hope this helped you a little!!!
Let the three consecutive natural numbers be(x+1), (x+2), (x+3).
(x+1) + (x+2) +(x+3) = 60
x+1+x+2+x+3 =60
3x + 6 =60
3x =60-6
3x =54
x = 54/3
x =18
hence, the three consecutive natural numbers are
(18+1)=19,
(18+2)=20,
(18+3)=21
The total value 19+20+21=60.
Hope this helped you a little!!!
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