Question

find the three consecutive odd numbers whose sum is 987
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Answer 1

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$\longrightarrow x + (x + 2) + (x + 4) = 987$

$\longrightarrow 3x + 6 = 987$

$\longrightarrow 3x = 987 - 6$

$\longrightarrow 3x = 981$

$\longrightarrow x = 981/3$

$\longrightarrow x = 327$

Other numbers :

$\longrightarrow (x + 2) = (327 + 2) = 329$

$\longrightarrow (x + 4) = (327 + 4) = 331$

Therefore, the numbers are 327, 329 and 331.

Answer 2

Answer:

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ᴀɴsᴡᴇʀ࿐}}}$

$\longrightarrow x + (x + 2) + (x + 4) = 987$

$\longrightarrow 3x + 6 = 987$

$\longrightarrow 3x = 987 - 6$

$\longrightarrow 3x = 981$

$\longrightarrow x = 981/3$

$\longrightarrow x = 327$

Other numbers :

$\longrightarrow (x + 2) = (327 + 2) = 329$

$\longrightarrow (x + 4) = (327 + 4) = 331$

Therefore, the numbers are 327, 329 and 331.