find the three consecutive positive even integer whose sum is 90
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Answered by
4
let the 1st number= x
thus 2nd number = x-1
3 rd number = x-2
x+x-1+x-2 = 90
3x-3= 90
3x= 90+3
3x=93
x=93÷3
x=31
1st no.=31
2nd no.=30
3rd no.= 29
thus 2nd number = x-1
3 rd number = x-2
x+x-1+x-2 = 90
3x-3= 90
3x= 90+3
3x=93
x=93÷3
x=31
1st no.=31
2nd no.=30
3rd no.= 29
Answered by
1
x+x+2+x+4=90
=3x+6=90
=3x=90-6=84
x=84/3
x=28
hope help u.
=3x+6=90
=3x=90-6=84
x=84/3
x=28
hope help u.
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