Find the three consecutive positive even integer whose sum is 90.
Answers
Answered by
4
Let the positive even numbers be n, n+2, n+4
Given that n+n+2+n+4=90
3n+6=90
3n=84
n= 28
Therefore the numbers are 28, 30, 32.
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Given that n+n+2+n+4=90
3n+6=90
3n=84
n= 28
Therefore the numbers are 28, 30, 32.
If u find it useful then please mark it as brainliest
Answered by
6
heya!! mate^_^
your answer is - - - -
let the numbers
(x)
(x+1)
(x+2)
x+x+1+x+2=90
3x+3=90
3x=90-3
3x= 87
x= 87/3
x=29
so,
numbers will be
x=29
x+1= 29+1=30
x+2= 29+2=31
your answer is - - - -
let the numbers
(x)
(x+1)
(x+2)
x+x+1+x+2=90
3x+3=90
3x=90-3
3x= 87
x= 87/3
x=29
so,
numbers will be
x=29
x+1= 29+1=30
x+2= 29+2=31
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