Math, asked by kunalrabidas2004, 1 year ago

Find the three different solutions for the equation 3x-8y=27

Answers

Answered by Tanay123456789
23
3x-8y=27

put value of y=0

3x-8(0)=27

3x=27

x=27/3

x=9

first solution=(9,0)

2.3x-8y=27

put value of x=1 

3(1)-8y=27

3-8y=27

-8y=27-3

-8y=24

y=-24/8

y=-3

second solution=(1,-3)

3.3x-8y=27

put value of y=3

3x-8(3)=27

3x-24=27

3x=27+24

3x=51

x=51/3

x=17.

third solution=(17,3).
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Answered by Rushikeshswami
4
put x= 1
3 - 8y = 27
8y = - 24
y = -3

put x= 2
6 - 8y = 27
8y = - 21
y = - 21/8

put x = 3
9 - 8y = 27
8y = - 18
y = -9/4






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