Math, asked by raj6631, 1 year ago

find the three digit greatest number that is divisible by both 2 and 3

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Answered by ArchitectSethRollins
4

 \boxed{hello}

Greatest Three digit number divisible by both 2 and 3 = ?

Now,
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A number which is divisible by both 2 & 3 , is divisible by (2 × 3) = 6

So,

Greatest Three digit number = 999

Dividing 999 by 6 , we get

6) \: 999 \: (166 \\  -  \: 6 \\  -  -  -  -  -  \\  \:  \:  \:  \: 39 \\  - 36 \\  - -  -   -  \\  \:  \:  \:  39 \\  - 36 \\  -  -  -  -  - -  -  -  \\ 3

Remainder = 3

So, The greatest 3 digit number divisible by 2 & 3 both = (999 - 3) = 996
Answered by ARYAyadav
0
99x where x is unit place digit
if three digit no. is divisible by 2 as well as 3 therefore it is also divisible by 6
as 996 is divisible by both 2 & 3

so, x = 6

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