Find the three geometric means between 15 and 1215
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a=15
So
15, m1, m2, m3, 1215
1215 = 5th term
ar^4=1215
15× r^4=1215
r^4=1215÷15
r^4=81
r=3
m1=ar=15× 3=45
m2=ar²=15×3×3=135
m3=ar³=15× (3³)=405
Solved.......
So
15, m1, m2, m3, 1215
1215 = 5th term
ar^4=1215
15× r^4=1215
r^4=1215÷15
r^4=81
r=3
m1=ar=15× 3=45
m2=ar²=15×3×3=135
m3=ar³=15× (3³)=405
Solved.......
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