Question

Find the three no.s in the ratio 2:3:5 ,the sum of whose squares is 608

Answer 1

let 3 nos be 2x 3x 5x
by condition
$4 {x}^{2} + 9 {x}^{2} + 25 {x}^{2} = 608 \\ 38 {x }^{2} = 608 \\ {x }^{2} = 16 \\ x = 4$
sides are 8 12 20

Answer 2

Pls. find your answer in attachment.