Question

Find the three number in arithmetic progression whose sum amd product are 6 and 6

Answer 1

A/Q

a +a+d+a+2d=6

3a+3d=6

a+d=2

a=2-d

Also

a(a+d)(a+2d)=6

(2-d)(2-d+d)(2-d+2d)=6

(2-d) (2)(2+d)=6

(2-d)(2+d)=3

4-d^2=3

d^2=1

d=±1

if d=1 then a=1

then three terms =1,2,3

if d=-1 then a=3

now three terms=3,2,1

MARK BRAINLIEST

FOLLOW.