Question

The equivalent mass of a trivalent metal element is 9g eq-1 the molar mass of its anhydrous oxide is

Answer 1

n-factor of a trivalent metal element = 3

→ Molar mass = Equivalent mass x n-factor

→ Molar mass = 9 x 3 = 27

As it is a Trivalent metal, the formula of its oxide is

M₂O₃.

The molar mass of its oxide = (2 x 27) + (3 x 16) = 54 + 48 = 102 grams

Hope it helps!!