Question

find the three numbers in an ap whose sum and product are 6 and 6 respectively with explanation​

Answer 1

1,2,3 is the AP

1+2+3=6

1*2*3=6

Answer 2

Answer:

Step-by-step explanation:

Let the no be a-d,a,a+d

Now,

(a-d)+a+(a+d)=6

⇒3a=6

⇒a=2

again,

(a-d)*a*(a+d)=6

=a²-d²*a=6

=4-d²*2=6

=8-2d²=6

=2d²=2

d=1

∴the number are:

1,2,3