Math, asked by suppi27, 1 year ago

find the three numbers in an ap whose sum and product are 6 and 6 respectively with explanation

Answers

Answered by ukm9

1,2,3 is the AP

1+2+3=6

1*2*3=6

ukm9: a=2

suppi27: kk

suppi27: next

ukm9: (a-d)(a+d)a

ukm9: a2-d2(a)=6

suppi27: why

ukm9: substitute the value of a in a square and a.

suppi27: got it thanks so much for your help

ukm9: a+d(a-d)(a) =a square-dsquare x a

ukm9: ok

Answered by khushialli405

Answer:

Step-by-step explanation:

Let the no be a-d,a,a+d

Now,

(a-d)+a+(a+d)=6

⇒3a=6

⇒a=2

again,

(a-d)*a*(a+d)=6

=a²-d²*a=6

=4-d²*2=6

=8-2d²=6

=2d²=2

d=1

∴the number are:

1,2,3

suppi27: thanks

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