Question

Find the three numbers in G.P. whose sum is 19 and whose product is 216

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Answer 1

Here's your solution buddy

Answer 2

Answer:9,6,4

Step-by-step explanation:

Let the number be a/r, a, ar

a/r+ a +ar =19

a/r*a*ar=219

a^3= 216

a=6

a+ar+ar^2 = 19r

6+6r+6r^2=19r

6r^2-13r+6 =0

6r^2-9r-4r+6=0

3r(2r-3)-2(2r-3)=0

(2r-3)(3r-2)=0

r=3/2 OR r=2/3

Now,

when r=3/2

a/r = 6/(3/2) =4

a=6

ar = 9

4,6,9

OR r=2/3

a/r = 6/(2/3) =9

a= 6

ar = 4

9,6,4