Math, asked by khushibinwal81, 3 months ago

Find the time in which Rs. 2,500 amount to Rs. 3,100 at 8% per annum.​

Answers

Answered by Anonymous
3

 \\  \\ \large\underline{ \underline{ \sf{ \red{given:} }}}  \\  \\

  • Principal = 2500 Rs

  • Amount = 3100 Rs

  • Rate of interest = 8% / annum

 \\  \\ \large\underline{ \underline{ \sf{ \red{to \: find:} }}}  \\  \\

  • Time taken in which 2500Rs to 3100 Rs at 8% rate of interest.

 \\  \\ \large\underline{ \underline{ \sf{ \red{solution:} }}}  \\  \\

Simple interest = Amount - Principal

Simple interest = 3100 - 2500

Simple interest = 600 Rs

We know ,

 \\   \\  \bigstar  \boxed{ \bf \: S.I =  \frac{PRT}{100} } \\  \\

Hence ,

 \\   \\ \bigstar \boxed{  \sf \:  \blue{T =  \frac{SI \times 100}{PR}}}  \\  \\

Putting values , we get..

 \\  \\  \sf \: T =  \frac{600 \times 100}{2500 \times 8}  \\  \\  \sf \: T =  \frac{60000}{20000}  \\  \\  \boxed{ \sf \: \green{ T  = 3yrs}} \\  \\

Hence , it will take 3yrs for 2500Rs to 3100Rs at rate of 8% per annum.

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