find the time in which the interest will be equal to the principal at the rate of 20% per year
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Principal = Rs.20000
Rate r = 20% =0.20
No. of compounds per year n = 4
Time = 1 year
Formula : A = P(1+\frac{r}{n})^{nt}
Where A= Amount
P = Principal
r = rate of interest
n = No. of compounds
t = time
A = P(1+\frac{r}{n})^{nt}
A = 20000(1+\frac{0.2}{4})^{4}
A=24310.125
Compound interest = Amount - Principal = 24310.125-20000 = Rs.4310.125
Hence The compound interest is Rs.4310.125
thank you ❤️...
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