Question

Find the time period of a 6m long rod swinging about one of it's ends in seconds(assume g=πsquare)​

Answer 1

Answer:

Time period of simple pendulum is given by T1=2πgl

Time period of a physical pendulum is given by T2=2πMglcmI

Where,

I=12Ml2+4Ml2=3Ml2 and lcm=2l

So we have,

T2=2πMg(2l)(3Ml2)⇒T2=2π3g2l

⇒T2T1=