find the time taken by a body of mass 16kg to come to rest from a uniform velocity of magnitude 10 m/s , when a force of 4n is applied continuously on it
a) 20s. b) 30s
c) 50s d) 40s
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Since, Force = 4N M x A = 4N (f=ma) 16kg x A = 4N. (m = 16kg) [ A = -1/4 m/s² ] Now, From 1st eq. of motion v = u+at 0 = 10 + (-1/4)t t = -4 x -10 [ t = 40 sec]
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