find the time when ₹1250 amounts to ₹1950 at 16% per annum
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siddhartharao77:
3.5 years.
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Answered by
41
principal=1250
amount=1950
rate=16%p.a.
S.I.=amount - principal
S.I.=1950-1250=700
time=100*S.I./P*R
100*700/1250*16
7/2=3.5 years or 3 and a half year
amount=1950
rate=16%p.a.
S.I.=amount - principal
S.I.=1950-1250=700
time=100*S.I./P*R
100*700/1250*16
7/2=3.5 years or 3 and a half year
Answered by
30
Heya friend,
____________________________________
Given that
A = ₹1,950
P = ₹1,250
R = 16 % p.a.
S. I. = A - P
= ₹(1,950-1,250)
= ₹700
S. I. = P×R×T/100
=> 700 = 1,250×16×T/100
=> 700 = 200T
=> T = 700/200
=> T = 7/2 years
=> T = 3 unit 1/2 years
Thanks
With regards@
Tanisha
____________________________________
Given that
A = ₹1,950
P = ₹1,250
R = 16 % p.a.
S. I. = A - P
= ₹(1,950-1,250)
= ₹700
S. I. = P×R×T/100
=> 700 = 1,250×16×T/100
=> 700 = 200T
=> T = 700/200
=> T = 7/2 years
=> T = 3 unit 1/2 years
Thanks
With regards@
Tanisha
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