Question

find the time when
i. principal = 300 , simple interest = 6.75 and rate = 4.5 % p.a
ii. principal = 4000 , simple interest = 250 and rate = 5 % p.a
answer i. 6 months
answer ii. 1 year 3 months

Answer 1

Answer:

i. SI = PRT/100

=> T = SI x 100 / P x R

=> T = 6.75 x 100 / 300 x 4.5

=> T = 675/1350.0

=> T = 1/2

=> T = 6 Months (1/2 of a year (12 months))

ii. T = i x 100

P x R

=> T = 250 x 1oo

4000x 5

=> T = 50 x 1

40 x 1

=> T = 5 of a year ( 12 months)

4

=> T = 15 Months / 1 Year 3 Months / 1 ¹/4

Step-by-step explanation:

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Answer 2

Given:

i. principal = $300$ , simple interest = $6.75$ and rate = $4.5$ % p.a

ii. principal = $4000$ , simple interest = $250$ and rate =$5$ % p.a

We have to find the time.

As we know that the simple Interest of an amount is calculated by multiplying the interest rate by the principal amount and the time period. the time period in years.

The formula is used to calculate the simple interest is:

$S I=\frac{P R T}{100}$

Where,

$P= Principal\ Amount\\T= Time\ in\ Years\\R= Rate\ of\ Interest\ per\ Annum.$

We are solving in the following way:

here,

i. principal = $300$ , simple interest = $6.75$ and rate = $4.5$ % p.a

Now,

$S I=\frac{P R T}{100}$

$=>6.75=\frac{300\times4.5\times T}{100} \\\\=>\frac{6.75\times 100}{300\times4.5} =T\\\\=>T=\frac{1}{2} year$

And

ii. principal = $4000$ , simple interest = $250$ and rate =$5$ % p.a

$S I=\frac{P R T}{100}$

$=>250=\frac{4000\times5\times T}{100} \\\\=>T=\frac{250\times100}{4000\times5} \\\\=>T=\frac{5}{4} \\\\=>T=1.25$

Hence, the time will be:

$i) \ 1/2 years\\ii)\ 1.25years$