Question

find the time when P is equal to rupees 6400 a are is equal to 6% p.a. simple interest is equal to Rupees 1152​

Answer 1

Answer:

T=3

Step-by-step explanation:

T=si×100÷p×r. so T= 1152×100÷6400×6=3.so Time =3

Answer 2

Answer :

The time is 3 years.

Step-by-step explanation :

To Find,

• The time

Solution,

Given that,

• Principal = Rs. 6400
• Rate = 6%
• Simple interest = Rs. 1152

As we know that,

$\boxed{\bf{Time} \: \sf{= \dfrac{S.I. \times 100}{P \times R}}}$

Where,

• T = Time
• S.I. = Simple interest
• P = Principal
• R = Rate

Therefore, time is,

$\bf{Time} \: \sf{= \dfrac{1152 \times 100}{6400 \times 6}} \\ \\ \sf{ \longrightarrow \: \dfrac{1152 \times \cancel{100}}{ \cancel{6400} \times 6}} \\ \\ \sf{\longrightarrow \: \dfrac{1152 \times 1}{64 \times 6}} \: \\ \\ \sf{\longrightarrow \: \dfrac{ \cancel{1152} \times 1}{64 \times \cancel{6}}} \\ \\ \sf{\longrightarrow \: \dfrac{192}{64}} \\ \\ \sf{\longrightarrow \: \cancel{\dfrac{192}{64}}} \\ \\ \bf{\longrightarrow \: 3 \: \: \bigstar}$

Therefore, the time is 3 years.

More Information

$\bullet \: \: {\bf{P} \: \sf{= \dfrac{S.I. \times 100}{R \times T}}}$

$\bullet \: \: {\bf{R} \: \sf{= \dfrac{S.I. \times 100}{P \times T}}}$

$\bullet \: \: {\bf{S.I.} \: \sf{= \dfrac{P \times R \times T}{100}}}$

$\bullet \: \: {\bf{Time} \: \sf{= \dfrac{S.I. \times 100}{P \times R}}}$