Question

In a solid, oxide ions are arranged in hcp. One third
of octahedral voids are occupied by the cations A and one sixth of the tetrahedral voids occupied by the cations B. What is the formula of the compound?​

Answer 1

Explanation:

• effective number of oxide ions=Zo2=6
• effective number of cationA=ZA=1/3x

octahedral voids = 1/3x6=2

• effective number of cation B=ZB=1/6x

tetraherdal voids 1/6x12=2

• formula of the compound =A2B2O6=ABO3