Math, asked by choudhryvaibhav3347, 1 year ago

Find the time when principal= Rs 6400, Simple Interest= Rs 1908 and Rate= 8%.

Answers

Answered by Anonymous
0
please comment me it is wrong or right
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Answered by BrainlyConqueror0901
1

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{Time=3.72\:years}}}\\

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{ \underline \bold{Given : }} \\   : \implies  \text{Principal(p)= 6400\:rupees} \\   \\   : \implies  \text{Simple \: interest(S.I) = 1908\:rupees} \\   \\   : \implies  \text{Rate(r) = 8\%} \\  \\ \red{ \underline \bold{To \: Find: }} \\  :  \implies  \text{Time(t) = ?}

• According to given question :

 \bold{As \: we \: know \: that  } \\   \circ \:  \text{Simple \: interest} =  \frac{ \text{Principal }\times \text{ Rate} \times  \text{Time}}{100}  \\  \\  \bold{Putting \: given \: values} \\   : \implies S.I =  \frac{p \times r \times t}{100}  \\  \\   : \implies  1908=  \frac{6400 \times 8\times t }{100}  \\  \\  :  \implies t =  \frac{ 1908\times 100}{6400 \times 8 }  \\  \\  \green{ :  \implies  \text{t = 3.72\: years}} \\  \\  \green{ \therefore  \text{Time = 3.72\: years}} \\  \\   \bold{some \: basic \: formula} \\  \circ \:  A = p(1 +   \frac{r}{100} )^{t}

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