Find the time when the speed of the particle becomes 3/4 of initial speed?
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If a is the deceleration. Then time t=-u/4a where u is initial speed
AnimeshNaroliya:
i need solution bro
There are 3 kinematic equations i.e.
V^2-u^2=2ax
X=ut+1/2at^2
V=u+at
Here we have 5 variables i.e. U,v,a,x,t
We have given v=3/4u so we have 4 variables and 3 equations. So we can't eliminate all variables.
V^2-u^2=2ax
X=ut+1/2at^2
V=u+at
Here we have 5 variables i.e. U,v,a,x,t
We have given v=3/4u so we have 4 variables and 3 equations. So we can't eliminate all variables.
V^2-u^2=2ax
So 2ax=-7/32u^2
Sorry
X=-7u^2/32a
Sub x in x=it+1/2at^2
1/2at^2 +ut +7u^2/32a=0
Even if u solve using quadratic earn formula to find t
We end up with variable a
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