find the tn for the Ap -3, 7, 17, 27...... and then find the 30th term for AP
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Answer:
287
Step-by-step explanation:
Term of APs are defined by a + ( n - 1 )d, where a is first term, d is the common difference and n is the number of term.
Here,
a = first term = - 3
d = 7 - ( - 3 ) = 7 + 3 = 10
So, Tn = a + ( n - 1 )d
= - 3 + ( n - 1 )10
= - 3 + 10n - 10
= 10n - 13
Hence 30th term is 10( 30 ) - 13 = 300 - 13 = 287
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