Physics, asked by jolbzcrespo, 2 months ago

Find the torque about the origin produced by a constant force of (6i+8j+10k) N on a particle situated at (3i-4k)m?

Answers

Answered by rjmalakar2002
1

Answer:

..

Explanation:

Force = 6i - 8j + 10k

It is given in the terms of components of vector.

So, first of all find it's magnitude.

Magnitude of force

\begin{gathered} = \sqrt{ {(6)}^{2} + {( - 8)}^{2} + {(10)}^{2} } \\ \\ = \sqrt{36 + 64 + 100} \\ \\ = \sqrt{200} \\ \\ = 14.142 \: newton\end{gathered}=(6)2+(−8)2+(10)2=36+64+100=200=14.142newton

Acceleration = 1 m/s^2

We know that,

Force = mass × acceleration

\begin{gathered}mass = \frac{force}{acceleration} \\ \\mass = \frac{14.142}{1} \\ \\ mass = 14.142 \: kg\end{gathered}mass=accelerationforcemass=114.142mass=14.142kg

So, the mass of the object is 14.142 kg.


jolbzcrespo: can you help another question? regarding on the my question above?
rjmalakar2002: ok
Answered by pratham7777775
12

Explanation:

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