Question

find the torque on 100 turns rectangular coil of
size 40cm*20cm,carrying a current of 10A and placed at an angle of 60 degree with the magnetic field of 5.0T.
answer is 200N

Answer 1

Answer:

200 N

Explanation:

Number of turns (n) = 100

Size of rectangular coil (A) = 40cm*20cm

Current (i) = 10 A

Magnetic field (B) = 5.0 T

It will make an angle of = (90° - 60°) = 30°

We know the torque is product of magnetic moment to the area.

Whereas magnetic moment is given by = current * no of turns * magnetic field

Hence, torque = BINA sin theta

= 5*10*100*(40×10^-2 * 20×10^-2) sin 30°

= 5000 * 800×10^-4 * 1/2

= 200 N