Find the total capacitance in the following figure:-
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Explanation:
2 F and 3 F are in series so ,
1/C23=1/C2+1/C3 = 1/2+1/3=3+2/6=5/6
C23=6/5=1.2F
similarly 4F and 5 F are in series so
1/C45=1/C4+1/5=1/4+1/5=5+4/20=9/20
C45 =20/9F
C23 and C45 are in parallel so,
Cnet=C23+C45 = 6/5+20/9 = 54+100/45 =154/45 =3.4F
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